std::literals::chrono_literals::operator""ms
From cppreference.com
| Defined in header <chrono>
|
||
constexpr std::chrono::milliseconds
operator""ms( unsigned long long ms );
|
(1) | (since C++14) |
constexpr std::chrono::duration</*unspecified*/, std::milli>
operator""ms( long double ms );
|
(2) | (since C++14) |
Forms a std::chrono::duration literal representing milliseconds.
1) Integer literal, returns exactly
std::chrono::milliseconds(ms).2) Floating-point literal, returns a floating-point duration equivalent to std::chrono::milliseconds.
Parameters
| ms | - | the number of milliseconds |
Return value
The std::chrono::duration literal.
Possible implementation
constexpr std::chrono::milliseconds operator""ms(unsigned long long ms)
{
return std::chrono::milliseconds(ms);
}
constexpr std::chrono::duration<long double, std::milli> operator""ms(long double ms)
{
return std::chrono::duration<long double, std::milli>(ms);
}
|
Notes
This operator is declared in the namespace std::literals::chrono_literals, where both literals and chrono_literals are inline namespaces. Access to this operator can be gained with:
using namespace std::literals,using namespace std::chrono_literals, orusing namespace std::literals::chrono_literals.
In addition, within the namespace std::chrono, the directive using namespace literals::chrono_literals; is provided by the standard library, so that if a programmer uses using namespace std::chrono; to gain access to the classes in the chrono library, the corresponding literal operators become visible as well.
Example
Run this code
#include <chrono>
#include <iostream>
int main()
{
using namespace std::chrono_literals;
constexpr auto d1{250ms};
constexpr std::chrono::milliseconds d2{1s};
std::cout << d1 << " = " << d1.count() << " milliseconds\n"
<< d2 << " = " << d2.count() << " milliseconds\n";
}
Output:
250ms = 250 milliseconds
1000ms = 1000 milliseconds
See also
| constructs new duration (public member function of std::chrono::duration<Rep,Period>)
|