std::literals::chrono_literals::operator""min
From cppreference.com
| Defined in header <chrono>
|
||
constexpr chrono::minutes
operator""min( unsigned long long mins );
|
(1) | (since C++14) |
constexpr chrono::duration</*unspecified*/, ratio<60,1>>
operator""min( long double mins );
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(2) | (since C++14) |
Forms a std::chrono::duration literal representing minutes.
1) Integer literal, returns exactly
std::chrono::minutes(mins).2) Floating-point literal, returns a floating-point duration equivalent to std::chrono::minutes.
Parameters
| mins | - | the number of minutes |
Return value
The std::chrono::duration literal.
Possible implementation
constexpr std::chrono::minutes operator""min(unsigned long long m)
{
return std::chrono::minutes(m);
}
constexpr std::chrono::duration<long double,
std::ratio<60,1>> operator""min(long double m)
{
return std::chrono::duration<long double, ratio<60,1>> (m);
}
|
Notes
This operator is declared in the namespace std::literals::chrono_literals, where both literals and chrono_literals are inline namespaces. Access to this operator can be gained with:
using namespace std::literals,using namespace std::chrono_literals, orusing namespace std::literals::chrono_literals.
In addition, within the namespace std::chrono, the directive using namespace literals::chrono_literals; is provided by the standard library, so that if a programmer uses using namespace std::chrono; to gain access to the classes in the chrono library, the corresponding literal operators become visible as well.
Example
Run this code
#include <chrono>
#include <iostream>
int main()
{
using namespace std::chrono_literals;
auto lesson = 45min;
auto halfmin = 0.5min;
std::cout << "One lesson is " << lesson.count() << " minutes"
" (" << lesson << ")\n"
<< "Half a minute is " << halfmin.count() << " minutes"
" (" << halfmin << ")\n";
}
Output:
One lesson is 45 minutes (45min)
Half a minute is 0.5 minutes (0.5min)
See also
| constructs new duration (public member function of std::chrono::duration<Rep,Period>)
|