std::chrono::weekday::operator+=, std::chrono::weekday::operator-=
来自cppreference.com
| |
(1) | (C++20 起) |
| |
(2) | (C++20 起) |
对星期之日值加或减 d.count(),将结果对 7 取余,规约成范围 [0, 6] 中的整数。
1) 实施
*this = *this + d;。2) 实施
*this = *this - d;。返回值
到修改后的此 weekday 的引用。
注解
调用这些函数之一后,若运算中不出现溢出,则 ok() 始终为 true。
示例
运行此代码
#include <chrono>
#include <iostream>
int main()
{
std::cout << std::boolalpha;
std::chrono::weekday wd{5}; // Friday is 5
wd += std::chrono::days(2);
std::cout << (wd == std::chrono::weekday(0)) << ' '
<< (wd == std::chrono::Sunday) << ' ';
wd -= std::chrono::days(3);
std::cout << (wd == std::chrono::weekday(4)) << ' '
<< (wd == std::chrono::Thursday) << ' ';
wd = std::chrono::Wednesday;
wd += std::chrono::days{8}; // ((3 += 8 == 11) % 7) == 4;
std::cout << (wd == std::chrono::Thursday) << ' ';
wd -= (std::chrono::Sunday - std::chrono::Tuesday); // -= -2
// (4 -= -2) == 6
std::cout << (wd == std::chrono::Saturday) << '\n';
}
输出:
true true true true true true
参阅
自增或自减 weekday (公开成员函数) | |
(C++20) |
在 weekday 上进行算术 (函数) |