std::list::merge
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<metanoindex/>
<tbody> </tbody> void merge( list& other ); |
(1) | |
void merge( list&& other ); |
(1) | (depuis C++11) |
template <class Compare> void merge( list& other, Compare comp ); |
(2) | |
template <class Compare> void merge( list&& other, Compare comp ); |
(2) | (depuis C++11) |
Fusionne deux listes triées en une seule. Les listes doivent être triées en ordre croissant .
Original:
Merges two sorted lists into one. The lists should be sorted into ascending order.
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Aucun élément n'est copié. Le
other récipient est vide après l'opération. La fonction ne fait rien si this == &other. Si get_allocator() != other.get_allocator(), le comportement est indéfini. Pas itérateurs ou les références deviennent invalidé, sauf que les itérateurs d'éléments déplacés maintenant se référer à *this, pas dans other. La première version utilise operator< de comparer les éléments, la deuxième version utilise la fonction de comparaison donnée comp .Original:
No elements are copied. The container
other becomes empty after the operation. The function does nothing if this == &other. If get_allocator() != other.get_allocator(), the behavior is undefined. No iterators or references become invalidated, except that the iterators of moved elements now refer into *this, not into other. The first version uses operator< to compare the elements, the second version uses the given comparison function comp.The text has been machine-translated via Google Translate.
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Paramètres
| other | - | un autre récipient de fusion
Original: another container to merge The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
| comp | - | comparison function which returns true if the first argument is less than the second. The signature of the comparison function should be equivalent to the following:
The signature does not need to have |
Retourne la valeur
(Aucun)
Original:
(none)
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Exemple
#include <iostream>
#include <list>
std::ostream& operator<<(std::ostream& ostr, const std::list<int>& list)
{
for (auto &i : list) {
ostr << " " << i;
}
return ostr;
}
int main()
{
std::list<int> list1 = { 5,9,0,1,3 };
std::list<int> list2 = { 8,7,2,6,4 };
list1.sort();
list2.sort();
std::cout << "list1: " << list1 << "\n";
std::cout << "list2: " << list2 << "\n";
list1.merge(list2);
std::cout << "merged: " << list1 << "\n";
}
Résultat :
list1: 0 1 3 5 9
list2: 2 4 6 7 8
merged: 0 1 2 3 4 5 6 7 8 9
Complexité
à la plupart des comparaisons
size() + other.size() - 1 .Original:
at most
size() + other.size() - 1 comparisons.The text has been machine-translated via Google Translate.
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Voir aussi
déplace les éléments d'un autre list Original: moves elements from another list The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (fonction membre publique) | |