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A393041
Number of trailing zeros in the primorial base representation of the arithmetic derivative of n.
5
0, 0, 1, 0, 0, 0, 2, 2, 0, 0, 1, 0, 0, 1, 1, 0, 0, 0, 2, 1, 0, 0, 1, 1, 0, 0, 1, 0, 0, 0, 1, 1, 0, 2, 3, 0, 0, 1, 1, 0, 0, 0, 2, 0, 0, 0, 1, 1, 0, 1, 1, 0, 0, 1, 1, 1, 0, 0, 1, 0, 0, 0, 2, 2, 0, 0, 2, 1, 0, 0, 2, 0, 0, 0, 1, 2, 0, 0, 1, 2, 0, 0, 1, 1, 0, 1, 1, 0, 0, 1, 2, 1, 0, 2, 1, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 2, 0, 0, 1
OFFSET
2,7
COMMENTS
A002110(a(n)) is the largest primorial that divides A003415(n).
FORMULA
a(n) = A276084(A003415(n)).
For n >= 0, a(A393042(n)) = n.
EXAMPLE
A003415(2) = 1, and A049345(1) = 1, with no (zero) trailing 0's, therefore a(2) = 0.
A003415(36) = 60, and A049345(60) = 2000, with three trailing 0's, therefore a(36) = 3.
PROG
(PARI)
A003415(n) = if(n<=1, 0, my(f=factor(n)); n*sum(i=1, #f~, f[i, 2]/f[i, 1]));
A276084(n) = { for(i=1, oo, if(n%prime(i), return(i-1))); }
CROSSREFS
Positions of terms 0..3 in this sequence are given by A235991 (0), A393043 (1), A393045 (2), A393047 (3).
Positions of nonzero terms are given by A235992 after its two initial terms.
Index of the first occurrence of n is given by A393042, that most likely are also positions of the records.
Sequence in context: A380955 A058190 A055736 * A006997 A141612 A316342
KEYWORD
nonn,base,easy
AUTHOR
Antti Karttunen, Feb 02 2026
STATUS
approved