std::chrono::year::operator+=, std::chrono::year::operator-=
From cppreference.com
constexpr std::chrono::year& operator+=( const std::chrono::years& y ) noexcept;
|
(1) | (since C++20) |
constexpr std::chrono::year& operator-=( const std::chrono::years& y ) noexcept;
|
(2) | (since C++20) |
Adds or subtracts y.count() years from the year value.
1) Equivalent to
*this = *this + y;.2) Equivalent to
*this = *this - y;.Return value
A reference to this year after modification.
Notes
If the result would be outside the range [-32767, 32767], the actual stored value is unspecified.
Example
Run this code
#include <chrono>
#include <iostream>
int main()
{
using namespace std::literals::chrono_literals;
std::cout << std::boolalpha;
std::chrono::year y{2020};
y += std::chrono::years(12);
std::cout << (y == 2032y) << ' ';
y -= std::chrono::years(33);
std::cout << (y == 1999y) << '\n';
}
Output:
true true
See also
| increments or decrements the year (public member function) | |
(C++20) |
performs arithmetic on years (function) |