std::rotl
From cppreference.com
| Defined in header <bit>
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template< class T >
constexpr T rotl( T x, int s ) noexcept;
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(since C++20) | |
Computes the result of bitwise left-rotating the value of x by s positions. This operation is also known as a left circular shift.
Formally, let N be std::numeric_limits<T>::digits and r be s % N.
- If
ris0, returnsx; - if
ris positive, returns(x << r) | (x >> (N - r)); - if
ris negative, returnsstd::rotr(x, -r).
This overload participates in overload resolution only if T is an unsigned integer type (that is, unsigned char, unsigned short, unsigned int, unsigned long, unsigned long long, or an extended unsigned integer type).
Parameters
| x | - | value of unsigned integer type |
| s | - | number of positions to shift |
Return value
The result of bitwise left-rotating x by s positions.
Notes
| Feature-test macro | Value | Std | Feature |
|---|---|---|---|
__cpp_lib_bitops |
201907L |
(C++20) | Bit operations |
Example
Run this code
#include <bit>
#include <bitset>
#include <cstdint>
#include <iostream>
int main()
{
using bin = std::bitset<8>;
const std::uint8_t x{0b00011101};
std::cout << bin(x) << " <- x\n";
for (const int s : {0, 1, 4, 9, -1})
std::cout << bin(std::rotl(x, s)) << " <- rotl(x, " << s << ")\n";
}
Output:
00011101 <- x
00011101 <- rotl(x, 0)
00111010 <- rotl(x, 1)
11010001 <- rotl(x, 4)
00111010 <- rotl(x, 9)
10001110 <- rotl(x, -1)
See also
(C++20) |
computes the result of bitwise right-rotation (function template) |
| performs binary shift left and shift right (public member function of std::bitset<N>)
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