std::experimental::propagate_const<T>::operator=
From cppreference.com
constexpr propagate_const& operator=( propagate_const&& p ) = default;
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(1) | (library fundamentals TS v2) |
template< class U >
constexpr propagate_const& operator=( propagate_const<U>&& pu );
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(2) | (library fundamentals TS v2) |
template< class U >
constexpr propagate_const& operator=( U&& u );
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(3) | (library fundamentals TS v2) |
propagate_const& operator=( const propagate_const& ) = delete;
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(4) | (library fundamentals TS v2) |
Let t_ designate the private data member that is the wrapped pointer-like object.
1) Explicitly defaulted move assignment operator that move assigns
this->t_ from p.t_.2) Assigns
This overload participates in overload resolution only if
std::move(pu.t_) to this->t_.This overload participates in overload resolution only if
U is implicitly convertible to T.
3) Assigns
This overload participates in overload resolution only if
std::forward<U>(u) to this->t_.This overload participates in overload resolution only if
U is implicitly convertible to T and std::decay_t<U> is not a specialization of propagate_const.
4) Copy assignment operator is explicitly deleted.
propagate_const is non-copyable.Parameters
| p | - | another propagate_const object to move from
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| pu | - | another propagate_const object of a different specialization to move from
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| u | - | another object to assign to the contained pointer |
Return value
*this.
