BERJAYA

>>> %matplotlib inline results in SyntaxError: invalid syntax
by Mike S Dec. 25, 2023

Dec. 25, 2023

I have installed Python 3.4.4 on XPSP3 and am trying to work my way through this tutorial. A Complete Tutorial on Ridge and Lasso Regression in Python http://www.analyticsvidhya.com/blog/2016/01/complete-tutorial-ridge-lasso-r… In Step 2 "Why Penalize the Magnitude of Coefficients?" we are shown this code: #Importing libraries. The same will be used throughout the article. import numpy as np import pandas as pd import random import matplotlib.pyplot as plt %matplotlib inline I get an error on the last line. I am running this code in Idle Python 3.4.4 Shell... Python 3.4.4 (v3.4.4:737efcadf5a6, Dec 20 2015, 19:28:18) [MSC v.1600 32 bit (Intel)] on win32 Type "copyright", "credits" or "license()" for more information. >>> import numpy as np >>> import pandas as pd >>> import random >>> import matplotlib.pyplot as plt >>> %matplotlib inline SyntaxError: invalid syntax What am I doing wrong? Suggested reading? TIA, Mike

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Re: How to add CC and BCC while sending mails using python
by akegb3＠gmail.com June 20, 2023

June 20, 2023

On Tuesday, September 30, 2008 8:00:16 AM UTC-8, Bernhard Walle wrote: > Hi, > > * cindy jones [2008-09-30 19:57]: > > > > Can someone tel me how to add cc's and bcc's while sending mails using > > python > > Following (tested) snippet should help: > > ------------------ 8< ------------------------------ > from smtplib import SMTP > from email.mime.image import MIMEImage > from email.mime.text import MIMEText > from email.mime.multipart import MIMEMultipart > > to = 'to_address(a)example.invalid' > cc = 'cc_address(a)example.invalid' > bcc = 'bcc_address(a)example.invalid' > > msg = MIMEMultipart() > msg['To'] = to > msg['Cc'] = cc > msg['From'] = 'bernhard(a)bwalle.de' > msg['Subject'] = 'Test' > text = MIMEText('Das ist ein Test') > text.add_header("Content-Disposition", "inline") > msg.attach(text) > > s = SMTP('test.smtp.relay') > s.sendmail(msg['From'], [to, cc, bcc], msg.as_string()) > s.quit() > ------------------ >8 ------------------------------ > > > Regards, > Bernhard Hello Bernhard, I've tried the above code and the bcc address does not receive the message, on the To & CC addresses receive it. Here are snippets from my code, perhaps something will stand out to you? to = 'ed(a)domain.gov' cc = 'ed(a)gmailmail.com' bcc = 'ed(a)home.net' msg = MIMEMultipart() msg['To'] = to msg['Cc'] = cc msg['Subject'] = 'My Subject text here' msg['From'] = 'edsboss(a)domain.gov' smtp = SMTP("smtpserver") smtp.ehlo() smtp.sendmail(msg['From'], [to, cc, bcc], msg.as_string()) Thanks in advance..hope you're still out there!! ~Ed

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Re: code blocks in Python
by hungjunglu＠yahoo.com March 25, 2022

March 25, 2022

Skip Montanaro <skip(a)pobox.com> wrote in message news:<mailman.1035.1069703636.702.python-list(a)python.org>... > > You should be able to express the desired semantics of your extension to the > language without requiring us to execute code. I have yet to see an > explanation of why you want > > def c: > x += 1 > > added to the language. I can guess that it binds c to a "code block". How > do I use it? The above is illegal syntax in Python today. Am I supposed to > guess how to use it? That has nothing to do with compile(). Am I supposed > to run it with the exec statement or do you envision me just inserting > > c > > into my code? Skip: being you a Python old timer, I think you are just grumbling for no good reason. :) Before anything else, people are already jumping into implementation details, optimization, syntax, etc. I am barely starting to look at whether there have been previous existing efforts, and if so, why were they discarded, etc. > > What exactly have you given me that I couldn't have done with > > x = 1 > x += 1 > I come back again to repeat it one more time: the compile() function already exists and works in Python. Before you do your posting, please think about the compile() function first. (Do I need to say it one more time? I don't mind.) So, let me try to pretend I am Skip Montanaro, and follow through with the process. (a) OK, I have been told that compile() function exists in Python. (b) I am complaining that I can do x = 1 x += 1 without resorting to codeblocks. So there is no need for codeblocks. Codeblocks are useless, good for nothing. (c) OK, one more time, I have been told that compile() function exists and works in Python. Everytime I talk about codeblocks, I need to think about the compile() function first. (d) Aha! So by analogy, there is no need for the compile() function in Python. I get it now! (e) Wait a second... searching through the Python newsgroup archive I find hundreds if not thousands of messages related to the usage of the compile() function. So the compile() function can't be useless. Either thousands of Python users are wrong, or I have not been careful in my thinking process. (f) Hmm... let me look at those messages and try to understand how people are using the compile() function. (g) Aha! The compile() function is not useless. I know how to use it, now. (h) Aha! Codeblocks are not useless. (i) Aha! So codeblocks are analogous to the compile() function, the only difference is that codeblocks are compiled at compile time. The compile function compiles the code string at runtime. (j) Wait, I think Hung Jung has said everything before in his messages. Bingo! Now you get it. Hung Jung

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Converting py files to .exe and .dmg
by Brian Simms Feb. 18, 2022

Feb. 18, 2022

Hi there, I have done a lot of looking around online to find out how to convert Python files to .exe and .dmg files, but I am confused. Could someone provide pointers/advice as to how I can turn a Python file into a Windows .exe and Mac .dmg file. Thanks for any help.

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Pickle file and send via socket
by S.B Feb. 18, 2022

Feb. 18, 2022

Hello friends Does anyone know if it's possible to pickle and un-pickle a file across a network socket. i.e: First host pickles a file object and writes the pickled file object to a client socket. Second host reads the pickled file object from the server socket and un-pickles it. Can anyone provide a simple code example of the client and server sides? Thanks

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Re: Compute working days
by Casey Webster Aug. 19, 2021

Aug. 19, 2021

How about: from datetime import date, timedelta # Define the weekday mnemonics to match the date.weekday function (MON, TUE, WED, THU, FRI, SAT, SUN) = range(7) def workdays(start_date, end_date, whichdays=(MON,TUE,WED,THU,FRI)): ''' Calculate the number of working days between two dates inclusive (start_date <= end_date). The actual working days can be set with the optional whichdays parameter (default is MON-FRI) ''' delta_days = (end_date - start_date).days + 1 full_weeks, extra_days = divmod(delta_days, 7) # num_workdays = how many days/week you work * total # of weeks num_workdays = (full_weeks + 1) * len(whichdays) # subtract out any working days that fall in the 'shortened week' for d in range(1, 8 - extra_days): if (end_date + timedelta(d)).weekday() in whichdays: num_workdays -= 1 return num_workdays

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Re: Converting hex data to image
by dimplemathew.17＠gmail.com Feb. 1, 2021

Feb. 1, 2021

On Tuesday, March 12, 2019 at 2:53:49 PM UTC+5:30, Peter Otten wrote: > dimplemathew.17(a)gmail.com wrote: > > >> Save the image to a file (in binary mode!) and then try to open it with > >> an image viewer. The data may be corrupted. > > > > When i tried doing that it says Invalid Image... > > So it looks like the problem occurs somewhere before you are decoding the > image with the PIL... This is what i am doing : for associate in self.conn.response[:-1]: attributes = associate['attributes'] obj = { 'img':attributes['thumbnailPhoto'],} This img i am calling in my view and writing to the file...

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Strange terminal behavior after quitting Tkinter application
by Chris Nov. 4, 2020

Nov. 4, 2020

Hi, I'm puzzled by some strange behavior when my Python/Tkinter application quits (on linux): the terminal from which I started Python is messed up. If start up python, then import the code below, then start the program with Application(), then click the Quit button, my terminal never prints anything again (such as commands I type). <code> import Tkinter import sys class Application(Tkinter.Tk): def __init__(self,**config): Tkinter.Tk.__init__(self,**config) Tkinter.Button(self,text="Quit",command=self.quit_application).pack() def quit_application(self): sys.exit() </code> Can anyone tell me what I'm doing wrong? Thanks for your help. Chris

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pip 20.2 release, plus changes coming in 20.3
by Sumana Harihareswara Oct. 1, 2020

Oct. 1, 2020

On behalf of the Python Packaging Authority, I am pleased to announce that we have just released pip 20.2, a new version of pip. You can install it by running python -m pip install --upgrade pip. The highlights for this release are: - The beta of the next-generation dependency resolver is available - Faster installations from wheel files - Improved handling of wheels containing non-ASCII file contents - Faster `pip list` using parallelized network operations - Installed packages now contain metadata about whether they were directly requested by the user (PEP 376’s REQUESTED file) The new dependency resolver is *off by default* because it is *not yet ready for everyday use*. The new dependency resolver is significantly stricter and more consistent when it receives incompatible instructions, and reduces support for certain kinds of constraints files, so some workarounds and workflows may break. Please test it with the `--use-feature=2020-resolver` flag. Please see our guide on how to test and migrate, and how to report issues <https://pip.pypa.io/en/latest/user_guide/#changes-to-the-pip-dependency-res…>. We are preparing to change the default dependency resolution behavior and make the new resolver the default in pip 20.3 (in October 2020). This release also partially optimizes pip’s network usage during installation (as part of a Google Summer of Code project by McSinyx <https://summerofcode.withgoogle.com/projects/#5428041779511296>). Please test it with `pip install --use-feature=2020-resolver --use-feature=fast-deps` and report bugs to the issue tracker <https://github.com/pypa/pip/issues/new?template=bug-report.md>. This functionality is *still experimental* and *not ready for everyday use*. You can find more details (including deprecations and removals) in the changelog <https://pip.pypa.io/en/stable/news/>. As with all pip releases, a significant amount of the work was contributed by pip’s user community. Huge thanks to all who have contributed, whether through code, documentation, issue reports and/or discussion. Your help keeps pip improving, and is hugely appreciated. Specific thanks go to Mozilla (through its Mozilla Open Source Support <https://www.mozilla.org/en-US/moss/> Awards) and to the Chan Zuckerberg Initiative <https://chanzuckerberg.com/eoss/> DAF, an advised fund of Silicon Valley Community Foundation, for their funding that enabled substantial work on the new resolver. -- Sumana Harihareswara pip project manager via contract with PSF Changeset Consulting https://changeset.nyc

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Re: Symlinks already present
by Termoregolato Sept. 1, 2020

Sept. 1, 2020

Il 26/07/20 22:47, dn ha scritto: > Thus, compare the results of the two calls to detect a difference. I will try also another way, If I don't err symlinks and original directory have the same inode number (I talk about Linux, where I'm using the application). I've a lot of directories like this abcd efgh .ab dc de where last part can change depending on contents. The are symlinked in a tree of a different dir, divided in many other directories, like work/a/abcd efgh .ab dc de where generally there are 5-50 links. So I could, if correct, walk the directory, and keeping a small array with the inode numbers check if these numbers are duplicated. -- Pastrano con un altro account

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Python-list

July 2020