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A388063
Irregular triangle read by rows: T(n,k) is the total number of parts in all partitions of n with k designated summands, n >= 1, 1 <= k <= A003056(n).
4
1, 5, 10, 2, 21, 8, 26, 28, 50, 58, 3, 50, 128, 11, 85, 222, 37, 91, 372, 100, 130, 596, 216, 4, 122, 896, 451, 14, 210, 1278, 848, 46, 170, 1808, 1511, 122, 250, 2522, 2493, 302, 260, 3244, 4121, 626, 5, 341, 4392, 6301, 1284, 17, 290, 5522, 9622, 2402, 55
OFFSET
1,2
COMMENTS
Row n has length A003056(n) hence the first element of column k is in row A000217(k).
LINKS
G. E. Andrews, R. P. Lewis, and J. Lovejoy, Partitions with designated summands, Acta Arith. 105 (2002), no. 1, 51-66.
William Y. C. Chen, Kathy Q. Ji, Hai-Tao Jin, and Erin Y. Y. Shen, On the Number of Partitions with Designated Summands, arXiv:1208.2210 [math.CO], 2012.
EXAMPLE
Triangle begins:
1;
5;
10, 2;
21, 8;
26, 28;
50, 58, 3;
50, 128, 11;
85, 222, 37;
91, 372, 100;
130, 596, 216, 4;
122, 896, 451, 14;
210, 1278, 848, 46;
170, 1808, 1511, 122;
250, 2522, 2493, 302;
260, 3244, 4121, 626, 5;
341, 4392, 6301, 1284, 17;
290, 5522, 9622, 2402, 55;
...
For n = 4 and k = 1 there are 21 parts in all partitions of 4 with only one designated summand. They are [4'], [2'+ 2], [2 + 2'], [1'+ 1 + 1 + 1], [1 + 1'+ 1 + 1], [1 + 1 + 1'+ 1], [1 + 1 + 1 + 1'], so T(4,1) = 21.
For n = 4 and k = 2 there are 8 parts in all partitions of 4 with two designated summands. They are [3'+ 1'], [2'+ 1'+ 1], [2'+ 1 + 1'], so T(4,2) = 8.
KEYWORD
nonn,tabf
AUTHOR
Omar E. Pol, Sep 14 2025
EXTENSIONS
More terms from Sean A. Irvine, Sep 21 2025
STATUS
approved