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A385965
Decimal expansion of the absolute value of the coefficient [x^4] 1/Gamma(x).
2
0, 4, 2, 0, 0, 2, 6, 3, 5, 0, 3, 4, 0, 9, 5, 2, 3, 5, 5, 2, 9, 0, 0, 3, 9, 3, 4, 8, 7, 5, 4, 2, 9, 8, 1, 8, 7, 1, 1, 3, 9, 4, 5, 0, 0, 4, 0, 1, 1, 0, 6, 0, 9, 3, 5, 2, 2, 0, 6, 5, 8, 1, 2, 9, 7, 6, 1, 8, 0, 0, 9, 6, 8, 7, 5, 9, 7, 5, 9, 8, 8, 5, 4, 7, 1, 0, 7, 7, 0, 1, 2, 9, 4, 7, 8, 7, 7, 1, 3, 2, 3, 3, 5, 3, 2, 0, 0, 0, 2, 2, 2, 0, 0, 0, 0, 1, 8
OFFSET
0,2
COMMENTS
The Taylor series 1/Gamma(x) = Sum_{i>=1} c_i x^i starts with c_1 = 1, c_2 = gamma = A001620, c_3 = -0.655878... = -A070860 . c_4 = -0.04200263... , absolute value here. Recurrence (i-1)*c_i = gamma *c_{i-1} - Sum_{k=2..i-1} (-1)^k*zeta(k) * c_{i-k} .
LINKS
M. Abramowitz, I. A. Stegun, Handbook of Mathematical Functions, 6.1.34.
I. S. Gradsteyn, I. M. Ryzhik, Tables of Series and Products, Academic Press (2014) 8.321.2 gives recurrence.
Simon Plouffe, Table up to c_15, (2004)
J. W. Wrench, Concerning two series for the Gamma Function, Math. Comp. 22 (1968) 617-626, Table 5.
FORMULA
Equals (-4*zeta(3) +Pi^2*gamma -2*gamma^3)/12, gamma = A001620, zeta(3) = A002117, Pi = A000796.
EXAMPLE
-0.042002635034095235529003934875....
MAPLE
(4*Zeta(3)-Pi^2*gamma+2*gamma^3)/12 ; evalf(%) ;
MATHEMATICA
First[RealDigits[(Pi^2*EulerGamma - 2*EulerGamma^3 - 4*Zeta[3])/12, 10, 100, -1]] (* or *)
First[RealDigits[Module[{x}, SeriesCoefficient[1/Gamma[x], {x, 0, 4}]], 10, 100, -1]] (* Paolo Xausa, Aug 08 2025 *)
CROSSREFS
Cf. A001620 [x^2], A070860 [x^3], A385966 [x^5].
Sequence in context: A232833 A256269 A256279 * A363436 A277767 A107088
KEYWORD
nonn,cons
AUTHOR
R. J. Mathar, Jul 13 2025
STATUS
approved