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A382237
Numbers that are not divisible by the sum of any subset of their digits.
2
23, 29, 34, 37, 38, 43, 46, 47, 49, 53, 56, 57, 58, 59, 67, 68, 69, 73, 74, 76, 78, 79, 83, 86, 87, 89, 94, 97, 98, 203, 223, 227, 229, 233, 239, 249, 253, 257, 263, 267, 269, 277, 283, 293, 299, 307, 323, 329, 334, 337, 338, 346, 347, 349, 353, 356, 358, 359, 367, 373, 376, 377, 379, 380, 383, 386, 388, 389, 394, 397, 398, 403
OFFSET
1,1
COMMENTS
This sequence has density zero since no numbers with the digit '1' are in it. The sequence is infinite. Example: Numbers like 23, 203, 2003, 20003, etc. are included because none of them is divisible by 2, 3, or 5.
Conjecture: after a sufficiently large n this sequence grows faster than the prime numbers.
LINKS
EXAMPLE
358 is in the sequence because it can't be divided by 3, 5, 8, (3+5)=8, (3+8)=11, (5+8)=13 or (3+5+8)=16.
289 is not in the sequence because it can be divided by (8+9)=17.
MAPLE
filter:= proc(n) local L, S;
L:= convert(n, base, 10);
andmap(s -> s=0 or n mod s <> 0, map(convert, combinat:-choose(L), `+`))
end proc:
select(filter, [$1..1000]); # Robert Israel, Mar 19 2025
PROG
(PARI) isok(k) = my(d=digits(k)); forsubset(#d, s, my(ss=sum(i=1, #s, d[s[i]])); if (ss && !(k % sum(i=1, #s, d[s[i]])), return(0))); return(1); \\ Michel Marcus, Mar 27 2025
(Python)
from itertools import chain, combinations
def powerset(s): # skipping empty set
return chain.from_iterable(combinations(s, r) for r in range(1, len(s)+1))
def ok(n): return all(n%t!=0 for s in powerset(list(map(int, str(n)))) if (t:=sum(s))>0)
print([k for k in range(1, 404) if ok(k)]) # Michael S. Branicky, Apr 01 2025
CROSSREFS
KEYWORD
nonn,base
AUTHOR
Sergio Pimentel, Mar 19 2025
STATUS
approved