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A385678
Least prime p <= n^2 - 2*n + 4 such that the polynomial Sum_{k=1..n} phi(k)*x^(n-k) is irreducible modulo p, or 1 if such p does not exist, where phi is Euler's totient function given by A000010.
4
1, 2, 3, 1, 1, 7, 31, 13, 67, 7, 67, 13, 53, 7, 11, 19, 101, 239, 37, 23, 13, 103, 263, 89, 79, 29, 47, 23, 167, 317, 139, 73, 283, 7, 223, 71, 83, 29, 1117, 503, 83, 167, 811, 349, 17, 3, 263, 37, 157, 317, 11, 7, 43, 283, 17, 79, 193, 293, 257, 233
OFFSET
1,2
COMMENTS
Conjecture: a(n) > 1 for all n > 5.
Note that Sum_{k=1..4} phi(k)*x^(4-k) = (x + 1)*(x^2 + 2) and Sum_{k=1..5} phi(k)*x^(5-k) = (x^2 - x + 2)*(x^2 + 2*x + 2).
See also A385658 and A385676 for similar conjectures.
LINKS
FORMULA
a(9) = 67 since 67 = 9^2 - 2*9 + 4 is the least prime p such that the polynomial Sum_{k=1..9}phi(k)*x^(9-k) is irreducible modulo p.
MATHEMATICA
P[n_, x_]:=P[n, x]=Sum[EulerPhi[k]*x^(n-k), {k, 1, n}];
tab={}; Do[Do[If[IrreduciblePolynomialQ[P[n, x], Modulus->Prime[k]]==True, tab=Append[tab, Prime[k]]; Goto[aa]], {k, 1, PrimePi[n^2-2n+4]}];
tab=Append[tab, 1]; Label[aa]; Continue, {n, 1, 60}]; Print[tab]
PROG
(PARI) a(n) = forprime(p=2, n^2 - 2*n + 4, if (polisirreducible(Mod(sum(k=1, n, eulerphi(k)*x^(n-k)), p)), return(p))); 1; \\ Michel Marcus, Aug 04 2025
CROSSREFS
KEYWORD
nonn
AUTHOR
Zhi-Wei Sun, Aug 04 2025
STATUS
approved