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A237913
Smallest number m > 1 (not ending in a 0) such that m and the digit reversal of m have n prime factors (counted with multiplicity). Palindromes are included.
2
2, 4, 8, 88, 252, 2576, 21708, 2112, 4224, 8448, 44544, 48384, 2977792, 21989376, 405504, 4091904, 441606144, 405909504, 886898688, 677707776, 4285005824, 276486684672, 21128282112, 633498894336, 2701312131072, 6739855589376, 29142024192, 65892155129856, 4815463645184, 445488555884544
OFFSET
1,1
FORMULA
a(n) = min{A076886(n+1), A237912(n)}
EXAMPLE
252 is the smallest number such that 252 and its reverse (also 252) have 5 prime factors (2*2*3*3*7). So, a(5) = 252.
2576 is the smallest number such that 2576 and its reverse (6752) have 6 prime factors (2*2*2*2*7*23 and 2*2*2*2*2*211, respectively). So a(6) = 2576.
PROG
(Python)
import sympy
from sympy import factorint
def rev(x):
rev = ''
for i in str(x):
rev = i + rev
return int(rev)
def RevFact(x):
n = 2
while n < 10**8:
if n % 10 != 0:
if sum(list(factorint(n).values())) == x:
if sum(list(factorint(rev(n)).values())) == x:
return n
else:
n += 1
else:
n += 1
else:
n += 1
x = 1
while x < 100:
print(RevFact(x))
x += 1
CROSSREFS
KEYWORD
nonn,base
AUTHOR
Derek Orr, Feb 15 2014
EXTENSIONS
a(17)-a(21) from Giovanni Resta, Feb 23 2014
a(22)-a(30) from Max Alekseyev, Feb 08 2024
STATUS
approved