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A060582
If the final digit of n in base 3 is the same as a([n/3]) then this digit, otherwise a(n)= mod 3-sum of these two digits, with a(0)=0.
2
0, 2, 1, 1, 0, 2, 2, 1, 0, 2, 1, 0, 0, 2, 1, 1, 0, 2, 1, 0, 2, 2, 1, 0, 0, 2, 1, 1, 0, 2, 2, 1, 0, 0, 2, 1, 0, 2, 1, 1, 0, 2, 2, 1, 0, 2, 1, 0, 0, 2, 1, 1, 0, 2, 2, 1, 0, 0, 2, 1, 1, 0, 2, 1, 0, 2, 2, 1, 0, 0, 2, 1, 0, 2, 1, 1, 0, 2, 2, 1, 0, 2, 1, 0, 0, 2, 1, 1, 0, 2, 1, 0, 2, 2, 1, 0, 0, 2, 1, 0, 2, 1, 1, 0, 2
OFFSET
0,2
FORMULA
a(n) =(-a([n/3])-n) mod 3 =A060583(n) mod 3.
EXAMPLE
a(4)=0 since a([4/3])=a(1)=2, (4 mod 3)=1 and 3-2-1=0. a(5)=2 since a([5/3])=a(1)=2 and (5 mod 3)=2.
CROSSREFS
Cf. A060588.
Sequence in context: A369241 A308061 A339448 * A060450 A180918 A152146
KEYWORD
base,nonn
AUTHOR
Henry Bottomley, Apr 04 2001
STATUS
approved