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Devsh-Graphics-Programming
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shady
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/
/ simple example of the restructurer in action (see opt_restructize.c)
/
/ this function diverges, with both branches eventually calling bb3 then returning
/
/ /!\ there is no reconvergence happening in this function (except for the return itself)
/
/ to reconverge, one needs to use the control() construct, such as demonstrated in restructure3
/
/ to be absolutely clear: two distinct sets of threads will execute two different dynamic instances bb3
fn
f i32(varying bool b) {
branch
(b, bb1(), bb2());
cont
bb1() {
jump
bb3(6);
}
cont
bb2 () {
jump
bb3(7);
}
cont
bb3(varying i32 r) {
/
/ blah
return
(r);
}
}
/
/ f is equivalent (and should be turned back into) this function:
/
/ (modulo some dataflow jank that opt passes may or may not cleanup)
fn
g i32(varying bool b) {
val
r
=
if
i32(b) {
/
/ blah
return
(6);
} else {
/
/ blah
return
(7);
}
unreachable
();
}
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